Given two integer arrays nums1
and nums2
, return an array of their intersection. Each element in the result must be unique and you may return the result in any order.
Example 1:
Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2]
Example 2:
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Explanation: [4,9] is also accepted.
Constraints:
1 <= nums1.length, nums2.length <= 1000
0 <= nums1[i], nums2[i] <= 1000
class Solution {
public:
vector<int> intersection(vector<int>& nums1, vector<int>& nums2) {
vector<int> ans;
set<int> s;
set<int> s2;
for(int a:nums1)
s.insert(a);
for(int a:nums2)
s2.insert(a);
for(int a:s2){
if(s.count(a) == 1)
ans.push_back(a);
}
return ans;
}
};
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