Count the number of prime numbers less than a non-negative number, n
Special thanks to @mithmatt for adding this problem and creating all test cases.
int countPrimes(int n)
for(int i=; i<n; i++)
a[i] = i; for(int i=; i * <= n; i++)
if(i == )
a[i] = ;
} for(int j = i + i; j < n; j += i)
if(a[j] != )
a[j] = ;
} int count = ;
for(int i=; i<n; i++)
cout << a[i] << " ";
if(a[i] != )
cout << endl; return count;
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