2021-02-06 13:33:54 The title is shown in the picture above ：

prolog The code is as follows , I'm just learning ,  among =:= Mark equality judgment , =\= It's not equal , comma Express And Conditions , Semicolon identification Or conditions

%X Y Z  respectively   hundred   Ten   individual

% According to the condition 1 Can be launched   When  X = 6  when , Y  It's not equal to  8,2, Z  Also is not equal to 8,2
%  Not all of them

(X =:= 6,Y =\=8, Z =\= 2);
(X =\= 6,Y =:=8, Z =\= 2);
(X =\= 6,Y =\=8, Z =:= 2).

%  I didn't list all of them
((X =:= 1, Y =\= 1, Z =\= 4);
(X =:= 4, Y =\= 1, Z =\= 4);
(X =\= 6, Y =:= 6, Z =\= 4);
(X =\= 6, Y =:= 4, Z =\= 4);
(X =\= 6, Y =\= 1, Z =:= 6);
(X =\= 6, Y =\= 1, Z =:= 1)).
(( X =:= 0, Y =:= 6, Z =\= 2);
( X =:= 0, Y =:= 2, Z =\= 6);
( X =:= 0, Y =\= 6, Z =:= 2);
( X =\= 6, Y =:= 2, Z =:= 0);
( X =\= 0, Y =:= 6, Z =:= 2);
( X =\= 6, Y =:= 2, Z =:= 0)).
X =\= 7, X =\= 3, X =\= 8,
Y =\= 7, Y =\= 3, Y =\= 8,
Z =\= 7, Z =\= 3, Z =\= 8.

((X =:= 7, Y =\=8, Y =\= 0, Z =\=8, Z =\= 0);
(X =:= 0, Y =\=7, Y =\= 8, Z =\=7, Z =\= 8);
(Y =:= 8, X =\=7, X =\= 0, Z =\=7, Z =\= 0);
(Y =:= 0, X =\=7, X =\= 8, Z =\=7, Z =\= 8);
(Z =:= 8, X =\=7, X =\= 0, Y =\=7, Y =\= 0);
(Z =:= 7, X =\=8, X =\= 0, Y =\=0, Y =\= 8)).

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